If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(7^x)+12=7^(2x)
We move all terms to the left:
(7^x)+12-(7^(2x))=0
determiningTheFunctionDomain 7^x-7^2x+12=0
We move all terms containing x to the left, all other terms to the right
7^x-7^2x=-12
| F+f-13=3f | | y^2-5y+6,25=8 | | 10y^2=24y-126 | | -3(x-14)+9=6x+42 | | 13+f=3f | | 4a-2=3a-3 | | 3x+17=7x-4 | | -6b–-19b–10b–12b=18 | | x=14(-8,1) | | −1(10−x)=3(x+4) | | 13+3f=f | | 4x(3x−7)−19x2=x | | 5.2r-0.68=1.8 | | 45=3v+9 | | z/8=0.75 | | 3f-13=f | | y-1=(7)-1 | | 1/5w+3=6/5w | | y-1=7-1 | | −(10−x)=3(x+4) | | 2-(6x-4)=6x-2 | | -1x+5=-10 | | 8-2(y+3=-10 | | 3f-f=13 | | 7=3x-9 | | 9n-6=-3(2-3n) | | d2= 3 | | 2x+4(4x-1)=2+4x | | (4x+11)=(x*x-10) | | 4/5w+2=9/5w | | 2.7(x=1+0.3(3x+33) | | 7/9r+3=-4 |